For the Mathmaticians!!!

[Wassahman]

Are you good at math?


Complete the last two in this sequence:


1=3, 2=3, 3=5, 4=4, 5=4, 6=3, 7=5, 8=5, 9=4, 10=3, 11=?, 12=?


Now that you have probably guessed, explain the pattern.

[Observador]

i absolutly so no pattern in it i try to look at many types of rows. differences, * or + and to the power of it doesnt make any sense to me

[Negator]

Yea ive got nothing too...i tried doing a gaussian elimination and matrix multiplication but still came up short...

[Predaxus]

11=10 and 12=9

[Yuuji]

11=3 12=5

The range of the numbers are from 3 to 5.

First number: Start at 3
: repeat number (3)
: add 2 to range (5)
<<new cycle>>
: subtract one (4)
: repeat number (4)
: add 2 to range (since range tops at 5, you 'roll over' back to 3)
<<new cycle>>
: subtract one (roll over, back to 5)
: repeat number (5)
: add 2 to range (goes to 4)
<<new cycle>>
: subtract one (3)

Therefore after subtracting one:
:repeat number (3)
: add 2 to range (5)

[Conjar]

Much simpler than that:
Just count the letters if you spell out the numbers:
11(eleven)= 6
12(twelve)= 6

[LOL75]

Originally Posted by Conjar

Much simpler than that:
Just count the letters if you spell out the numbers:
11(eleven)= 6
12(twelve)= 6

LOL, so simple, but makes the most sense

[Yuuji]

Originally Posted by Conjar

Much simpler than that:
Just count the letters if you spell out the numbers:
11(eleven)= 6
12(twelve)= 6

*facepalms*

Well done Conjar. I think you are right.

Still have to wait for Wassahman to speak up, but by Occam's Razor yours is the better answer.

[Observador]

lol cant believe i fall for this type of riddle again..:P yeah that should be the answer btw yuuji would u like to trade u qpetz for q's? cuz if u dont need them i would be more than willing to help u get rid of them:P

[hype]

Damn i didnt see this earlier, it was sooo easy for me.. Nice job conjar..